Question

\[ \begin{array}{l} y=-\frac{1}{3} x+2 \\ y=-\frac{2}{3} x+4 \end{array} \] Click to select points on the graph. \[ y=-\frac{1}{3} x+2 \quad y=-\frac{2}{3} x+4 \] The solution is ( \( \square \) \( \square \) ).

          \[
\begin{array}{l}
y=-\frac{1}{3} x+2 \\
y=-\frac{2}{3} x+4
\end{array}
\]

Click to select points on the graph.
\[
y=-\frac{1}{3} x+2 \quad y=-\frac{2}{3} x+4
\]

The solution is ( \( \square \)
\( \square \) ).

y=-(1)/(3) x+2

y=-(2)/(3) x+4

Click to select points on the graph.

y=-(1)/(3) x+2 y=-(2)/(3) x+4

The solution is ( □
□ ).

Added by Karen F.

Algebra 1

Ron Larson, Laurie Boswell, Timothy D.… 1st Edition

Chapter 4

Instant Answer

Solved by Expert Nathan Smith

Step 1

\[ -\frac{1}{3}x + 2 = -\frac{2}{3}x + 4 \] Show more…

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\[ \begin{array}{l} y=-\frac{1}{3} x+2 \\ y=-\frac{2}{3} x+4 \end{array} \] Click to select points on the graph. \[ y=-\frac{1}{3} x+2 \quad y=-\frac{2}{3} x+4 \] The solution is ( \( \square \) \( \square \) ).