Question

CH3COOH(aq) + H2O(l) ? CH3COO-(aq) + H3O+(aq) Keq = Ka = 1.8 x 10-5 2 H2O(l) ? H3O+(aq) + OH-(aq) Keq = Kw = 1 x 10-14 CH3COO-(aq) + H2O(l) ? CH3COOH(aq) + OH-(aq) Keq = Kb = ?

          CH3COOH(aq) + H2O(l) ? CH3COO-(aq) + H3O+(aq) Keq = Ka = 1.8 x 10-5
2 H2O(l) ? H3O+(aq) + OH-(aq) Keq = Kw = 1 x 10-14
CH3COO-(aq) + H2O(l) ? CH3COOH(aq) + OH-(aq) Keq = Kb = ?
        
CH3COOH(aq) + H2O(l) ? CH3COO-(aq) + H3O+(aq) Keq = Ka = 1.8 x 10-5
2 H2O(l) ? H3O+(aq) + OH-(aq) Keq = Kw = 1 x 10-14
CH3COO-(aq) + H2O(l) ? CH3COOH(aq) + OH-(aq) Keq = Kb = ?

Added by Em D.

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Intermediate Algebra
Intermediate Algebra
Lynn Marecek 2nd Edition
Chapter 7
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Using the simple reactions below, along with their Keq’s, determine the Keq for the final reaction
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Transcript

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00:01 Here we are given with a reaction, right? what is that reaction? we need to calculate the kb, right? ch3c2o negative in aquos form plus you have h2o that is liquid, right? that gives ch3cw in aqua's form plus oh negative that is in aqua swarm again.
00:44 Right...
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