\begin{tabular}{|l|c|c|c|r|} \hline & Walk-In & TV Ad & Referred & Total \\ \hline Dissatisfied & 21 & 7 & 2 & \( \mathbf{3 0} \) \\ \hline Neutral & 18 & 24 & 37 & \( \mathbf{7 9} \) \\ \hline Satisfied & 26 & 41 & 61 & \( \mathbf{1 2 8} \) \\ \hline Very Satisfied & 31 & 35 & 44 & \( \mathbf{1 1 0} \) \\ \hline Total & \( \mathbf{9 6} \) & \( \mathbf{1 0 7} \) & \( \mathbf{1 4 4} \) & \( \mathbf{3 4 7} \) \\ \hline \end{tabular} A hair salon completed a survey of 347 customers. The results are organized into the table above. The categories of satisfaction level include: Dissatisfied, Neutral, Satisfied, or Very Satisfied. The categories of customer include: Walk-in, saw TV Ad, or was Referred. Assume the table represents the entire population of customers. Fill-in-the-blanks with the correct final answers. You must enter each answer as a FRACTION. For example, to say \( \frac{13}{27} \), type \( 13 / 27 \). Find the probability that a customer selected at random is: a. Satisfied: \( \square \) b. Neutral and Referred: \( \square \) c. Very Satisfied, given TV Ad: \( \square \) d. Dissatisfied or Walk-In: \( \square \)
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- Total number of customers surveyed = 347 - Number of customers who are Satisfied = 128 - Probability = Number of Satisfied customers / Total number of customers = 128 / 347 Show more…
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A hair salon conducted a survey of 354 customers to assess their satisfaction with the service and determine the type of customer. A walk-in customer is defined as someone who has not seen any advertisements and has not been referred to the salon. The remaining customers either saw a TV ad or were referred to the salon, but not both. The results of the survey are as follows: Walk-In TV Ad Referred Total Not Satisfied 19 11 5 35 Neutral 18 22 40 80 Satisfied 32 41 59 132 Very Satisfied 28 31 48 107 Total 97 105 152 354 Assuming that the sample represents the entire population of customers, we can calculate the following probabilities: 1. The probability that a customer is not satisfied. 2. The probability that a customer is not satisfied and is a walk-in. 3. The probability that a customer is very satisfied, given that they were referred. 4. The probability that a customer is neutral or referred. 5. The probability that a customer saw an ad and was referred.
Jen H.
A hotel claims that 90% of its customers are very satisfied with its service. Complete parts a through d below based on a random sample of eight customers. a. What is the probability that exactly seven customers are very satisfied? 0.3826 (Round to four decimal places as needed.) b. What is the probability that more than seven customers are very satisfied? 0.4305 (Round to four decimal places as needed.) c. What is the probability that less than six customers are very satisfied? (Round to four decimal places as needed.) d. Suppose that of eight customers selected, four responded that they are very satisfied. What conclusions can be drawn about the sample? The probability that 4 out of 8 customers are very satisfied is assuming that 90% of customers are very satisfied. Therefore, it is not likely that randomly selecting 8 customers would result in 4 responding that they are very satisfied. (Round to four decimal places as needed.)
Supreeta N.
A hair salon surveyed 319 customers (104 females and 215 males) to see if they are satisfied with the service. The results are summarized in the following table: Satisfied Not Satisfied Total Female 101 3 104 Male 208 7 215 Total 309 10 319 1. If a customer is randomly selected from these 319 people, the probability that he/she is satisfied is (Please round your answer to two decimal places) 2. If we know the selected customer is a female, then what is the probability that she is satisfied? (Please round your answer to two decimal places) P(satisfied|female) 3. How about the probability that a randomly selected customer is a female if we know that the person is satisfied? (Please round your answer to two decimal places) P(female|satisfied)
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