Question

\begin{tabular}{|l|l|l|l|} \hline Run & \begin{tabular}{l} {\( \left[\mathrm{S}_{2} \mathrm{O}_{3}{ }^{2}\right] \) in reaction } \\ mixture (M) \end{tabular} & Blackout time (s) & 1 /blackout time \( \left(\mathrm{s}^{-1}\right) \) \\ \hline 1 & 0.22 & 19.8 & \( 0.05 \mathrm{~s}^{-1} \) \\ \hline 2 & 0.19 & 21.3 & \( 0.05 \mathrm{~s}^{-1} \) \\ \hline 3 & 0.17 & 24.1 & \( 0.04 \mathrm{~s}^{-1} \) \\ \hline 4 & 0.14 & 29.9 & \( 0.03 \mathrm{~s}^{-1} \) \\ \hline 5 & 0.12 & 37.5 & \( 0.03 \mathrm{~s}^{-1} \) \\ \hline 6 & 0.09 & 48.7 & \( 0.02 \mathrm{~s}^{-1} \) \\ \hline \end{tabular}

          \begin{tabular}{|l|l|l|l|}
\hline Run & \begin{tabular}{l}
{\( \left[\mathrm{S}_{2} \mathrm{O}_{3}{ }^{2}\right] \) in reaction } \\
mixture (M)
\end{tabular} & Blackout time (s) & 1 /blackout time \( \left(\mathrm{s}^{-1}\right) \) \\
\hline 1 & 0.22 & 19.8 & \( 0.05 \mathrm{~s}^{-1} \) \\
\hline 2 & 0.19 & 21.3 & \( 0.05 \mathrm{~s}^{-1} \) \\
\hline 3 & 0.17 & 24.1 & \( 0.04 \mathrm{~s}^{-1} \) \\
\hline 4 & 0.14 & 29.9 & \( 0.03 \mathrm{~s}^{-1} \) \\
\hline 5 & 0.12 & 37.5 & \( 0.03 \mathrm{~s}^{-1} \) \\
\hline 6 & 0.09 & 48.7 & \( 0.02 \mathrm{~s}^{-1} \) \\
\hline
\end{tabular}

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Run
[S2O3^2] in reaction

mixture (M)
Blackout time (s) 1 /blackout time (s^-1)

1 0.22 19.8 0.05 s^-1

2 0.19 21.3 0.05 s^-1

3 0.17 24.1 0.04 s^-1

4 0.14 29.9 0.03 s^-1

5 0.12 37.5 0.03 s^-1

6 0.09 48.7 0.02 s^-1

Added by Sherry J.

General Chemistry: Principles and Modern Applications

Ralph H. Petrucci, F. Geoffrey Herring,… 10th Edition

Chapter 14

Instant Answer

Solved by Expert Courtney Sorensen

Step 1

The table provided shows the concentration of \( \mathrm{S}_{2} \mathrm{O}_{3}^{2-} \) in a reaction mixture, the blackout time in seconds for each run, and the reciprocal of the blackout time in seconds\(^{-1}\). The goal might be to analyze the relationship Show more…

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\begin{tabular}{|l|l|l|l|} \hline Run & \begin{tabular}{l} {\( \left[\mathrm{S}_{2} \mathrm{O}_{3}{ }^{2}\right] \) in reaction } \\ mixture (M) \end{tabular} & Blackout time (s) & 1 /blackout time \( \left(\mathrm{s}^{-1}\right) \) \\ \hline 1 & 0.22 & 19.8 & \( 0.05 \mathrm{~s}^{-1} \) \\ \hline 2 & 0.19 & 21.3 & \( 0.05 \mathrm{~s}^{-1} \) \\ \hline 3 & 0.17 & 24.1 & \( 0.04 \mathrm{~s}^{-1} \) \\ \hline 4 & 0.14 & 29.9 & \( 0.03 \mathrm{~s}^{-1} \) \\ \hline 5 & 0.12 & 37.5 & \( 0.03 \mathrm{~s}^{-1} \) \\ \hline 6 & 0.09 & 48.7 & \( 0.02 \mathrm{~s}^{-1} \) \\ \hline \end{tabular}

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