$ \begin{vmatrix} x & -1 \\ 3 & 1-x \end{vmatrix} = \begin{vmatrix} 1 & 0 & -3 \\ 2 & x & -6 \\ 1 & 3 & x-5 \end{vmatrix} $
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Step 1: Calculate the determinant of the 2x2 matrix on the left side: $ \begin{vmatrix} x & -1 \\ 3 & 1-x \end{vmatrix} = x(1-x) - (-1)(3) = x - x^2 + 3 $ Show more…
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