00:01
Hello students, the question is related to find asymmetric centers and optical isomers in the structure of isolucine.
00:08
You can see the structures i have labeled them as 1, 2, 3, 4, 5 carbons, right? now, if you see at the second carbon, you can see all the groups attached to that particular carbon are different.
00:18
That makes it asymmetric.
00:20
Similar manner, if you look at carbon number 3, here also all the groups attached to that carbon are different.
00:26
That also makes it as asymmetric center.
00:29
So, number of asymmetric centers we are having is 2.
00:32
They are carbon number 2 and carbon number 3.
00:35
Right? this is the first part.
00:37
Now, we have to find optical isomers.
00:40
The formula used would be 2 raise to the power n, where n stands for number of chiral centers.
00:47
Chiral or you can call them as asymmetric centers.
00:50
So 2 raise to the power 2.
00:53
That will give you answer 4.
00:56
Right? so number of optical isomers are 4.
00:58
Now what we are going to do is we are going to draw these optical isomers.
01:03
I'm going to make the difference at carbon second at carbon third.
01:08
So now at carbon second i'm going to make ammonium ion above the plane.
01:16
And the methyl group i'm going to make it below the plane...