00:01
Hello, the given buffer is tris buffer whose pkv value is 6 .01 having the mass 36 .762 gram present in hcl solution whose molarity, that is the concentration is given as 0 .104 molar in volume that is 1 .3 2 liter solution.
00:42
We need to find out over here the ph of buffer.
00:48
What will be the ph of the buffer? the given buffer is t -r -i -s buffer.
00:58
If we will write its structural formula, it will be c -o -h -c -h -h -2, whole 3 -3.
01:12
From this structural formula the molecular weight of the tris is found to be 1201 .14 gram per mole hence the number of moles for t rias will be mass divided by molar mass as it is given the mass is 36 .76 762 gram divided by its molar mass 121 .14 which will be equals to 0 .30 mole.
01:52
From this we can calculate the concentration of the trias as we know that concentration is moles per liter.
02:02
The mole is found to be 0 .30 mole and the solution's volume is given as 1 .3.
02:10
3 2 liter that will result 0 .2 molar.
02:19
We know that p .k .a plus pkb is equal to 14.
02:27
Hence pka will be 14 minus pkb.
02:34
The value of pkb is given to us as 14 minus 6 .01 that is equal to 7 .99...