00:01
Hello everyone, we are going to understand this question here.
00:06
Data from the given circuit diagram, data given from the diagram from the given circuit diagram in the question.
00:30
Here, value of r1, that is 33 om, value of r2 that is 48 ome, and value of r3 that is 60 oom.
00:48
Here we have to find the current equivalent resistance and potential.
01:02
Current across each register, potential across each register and equivalent resistance.
01:13
Here we can see that r2 and r3 are in parallel connected.
01:18
So equivalent of r2 and r3 that is represented by r23.
01:24
So we can write r2 plus 1 upon r3.
01:29
Here, value of r2 is 48, 1 upon 48 plus 1 upon 60.
01:40
Now taking lcm, so we can write, so after calculation we will get r2 3 is equal to 60 into 48 upon 60 plus 48.
01:55
So after calculation we will get 108 into 60 into 48 om.
02:04
Now doing further calculation, so we will get r2 3 is equal to 9 into 5 into 48.
02:23
After doing further calculation, we will get r2 3 is equal to, after calculation we will get 26 .7 oom.
02:34
26 .7 oom.
02:37
This is the equivalent resistance across the circuit.
02:41
Sorry, this is the equivalent resistance of 2, r2 and r3.
02:48
Now calculating equivalent resistance, that is r equivalent is equal to r1 plus r23, here value of r1 is 33 om plus r23 is 26 .7 om.
03:06
So after calculation we will get 59 .7 om.
03:14
This is the required equivalent resistance.
03:18
Now calculating current, so i -i -1 is equal to or we can write net current across the circuit that is represented by i, i is equal to v by r equivalent.
03:32
Here value of v is 8 and r equivalent is 59 .7...