00:01
Alright, so if i'm interpreting the problem description correctly, we have an inclined plane with a pulley at the top, and this pulley has a string running over it that connects two blocks.
00:10
One of them is on the inclined plane, and one of them is off of it.
00:14
And it looks like block b is the block on the horizontal part, block a is the block there.
00:22
So we're told the mass of block a is 4 .4 kilograms, and the mass of block b is.
00:30
Half that so 2 .2 and the incline that block a is situated on is 31 degrees and the coefficient of friction between block b and the horizontal surface is 0 .54 the kinetic coefficient of friction and so we want to find the tension in the cord and the magnitude of the acceleration of the blocks so if we draw a free body diagram of block a what we're going to have is the tension going to this way.
01:02
The weight of the block, of course, going down.
01:05
So this is ma times g.
01:07
And then the component of the weight that is along the plane is mag sine theta.
01:14
And we're told the incline plane is frictionless.
01:16
So we don't need to worry about any frictional force.
01:19
But we will also have the normal force, you know, which is mag times the cosine theta.
01:25
And then for block b, what we'll have is the tension going to the left.
01:29
And then the frictional force presumably opposing this.
01:34
And so if we write out newton's second law for each block, we'll have block a times its acceleration...