Question

A block of mass m? = 16.0 kg is connected to a block of mass m? = 40.0 kg by a massless string that passes over a light, frictionless pulley. The 40.0-kg block is connected to a spring that has negligible mass and a force constant of k = 240 N/m as shown in the figure below. The spring is unstretched when the system is as shown in the figure, and the incline is frictionless. The 16.0-kg block is pulled a distance h = 16.0 cm down the incline of angle ? = 40.0° and released from rest. Find the speed of each block when the spring is again unstretched. v_m1 = m/s v_m2 = m/s

          A block of mass m? = 16.0 kg is connected to a block of mass m? = 40.0 kg by a massless string that passes over a light, frictionless pulley. The 40.0-kg block is connected to a spring that has negligible mass and a force constant of k = 240 N/m as shown in the figure below. The spring is unstretched when the system is as shown in the figure, and the incline is frictionless. The 16.0-kg block is pulled a distance h = 16.0 cm down the incline of angle ? = 40.0° and released from rest. Find the speed of each block when the spring is again unstretched.
v_m1 = m/s
v_m2 = m/s
        
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A block of mass m? = 16.0 kg is connected to a block of mass m? = 40.0 kg by a massless string that passes over a light, frictionless pulley. The 40.0-kg block is connected to a spring that has negligible mass and a force constant of k = 240 N/m as shown in the figure below. The spring is unstretched when the system is as shown in the figure, and the incline is frictionless. The 16.0-kg block is pulled a distance h = 16.0 cm down the incline of angle ? = 40.0° and released from rest. Find the speed of each block when the spring is again unstretched.
vm1 = m/s
vm2 = m/s

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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A block of mass m₁ = 16.0 kg is connected to a block of mass mā‚‚ = 40.0 kg by a massless string that passes over a light, frictionless pulley. The 40.0-kg block is connected to a spring that has negligible mass and a force constant of k = 240 N/m as shown in the figure below. The spring is unstretched when the system is as shown in the figure, and the incline is frictionless. The 16.0-kg block is pulled a distance h = 16.0 cm down the incline of angle Īø = 40.0° and released from rest. Find the speed of each block when the spring is again unstretched. v_m1 = m/s v_m2 = m/s
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A 20.0 -kg block is connected to a $30.0-\mathrm{kg}$ block by a string that passes over a light frictionless pulley. The $30.0-\mathrm{kg}$ block is connected to a spring that has negligible mass and a force constant of $250 \mathrm{N} / \mathrm{m},$ as shown in Figure $\mathrm{P} 8.59$ . The spring is unstretched when the system is as shown in the figure, and the incline is frictionless. The $20.0-\mathrm{kg}$ block is pulled 20.0 $\mathrm{cm}$ down the incline (so that the $30.0-\mathrm{kg}$ block is 40.0 $\mathrm{cm}$ above the floor) and released from rest. Find the speed of each block when the $30.0-\mathrm{kg}$ block is 20.0 $\mathrm{cm}$ above the floor (that is, when the spring is unstretched).

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A 20.0 -kg block is connected to a $30.0-\mathrm{kg}$ block by a string that passes over a light frictionless pulley. The $30.0-\mathrm{kg}$ block is connected to a spring that has negligible mass and a force constant of $250 \mathrm{N} / \mathrm{m},$ as shown in Figure $\mathrm{P} 8.59$ . The spring is unstretched when the system is as shown in the figure, and the incline is frictionless. The $20.0-\mathrm{kg}$ block is pulled 20.0 $\mathrm{cm}$ down the incline (so that the $30.0-\mathrm{kg}$ block is 40.0 $\mathrm{cm}$ above the floor) and released from rest. Find the speed of each block when the $30.0-\mathrm{kg}$ block is 20.0 $\mathrm{cm}$ above the floor (that is, when the spring is unstretched).

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Transcript

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00:01 We'd like to find the speed of each block.
00:04 So our total energy is our sum of our potential and our gravitational potential energy.
00:09 So let's find our total energy.
00:12 That's going to be one -half kx squared plus mass 2, gravity times height.
00:17 So we can plug in 1 -half times 240 times 0 .16 squared, plus 40 times 9 .8 times our 0 .16 meters.
00:29 So let's plug this into a calculator to find our total energy.
00:33 We have one -half times 240 times .16 squared, plus 40 times 9 .8 times .16 gives us 65 .7 joules as our total energy.
00:47 Now we want to find our total kinetic energy.
00:51 Our kinetic energy is one -half mass 1v squared plus 1⁄2v squared.
00:58 So this will be one half times the sum of our masses, which is 16 plus 40, so that's 56 v squared, or 28 v squared...
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