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Bode plots for G(s)=(40)/(10s+400) Sketch the bode plots and show work on how to get the answers for the graph Bode plots for $G(s) = \frac{40}{10s + 400}$

Name: bode plots for gs4010s400 sketch the bode plots and show work on how to get the answers for the graph bode plots for gs frac4010s 400 75748
Uploaded: 2022-02-26T05:26:50-08:00
Duration: 1 min 59 s
Channel: Amit Srivastava
Description: bode plots for gs4010s400 sketch the bode plots and show work on how to get the answers for the graph bode plots for gs frac4010s 400 75748

          Bode plots for G(s)=(40)/(10s+400)
Sketch the bode plots and show work on how to get the answers for the graph
Bode plots for $G(s) = \frac{40}{10s + 400}$

$bode plots for gs4010s400 sketch the bode plots and show work on how to get the answers for the graph bode plots for gs frac4010s 400 75748$

Added by Jose Carlos L.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Amit Srivastava

02/26/2022

Step 1

We can rewrite this as: $G(s) = \frac{40}{400(1 + \frac{10s}{400})} = \frac{0.1}{1 + 0.025s}$ This is a first-order system with a DC gain of 0.1 and a time constant of $\tau = \frac{1}{0.025} = 40$. The corner frequency is $\omega_c = \frac{1}{\tau} = 0.025 Show more…

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Bode plots for G(s)=(40)/(10s+400) Sketch the bode plots and show work on how to get the answers for the graph Bode plots for $G(s) = \frac{40}{10s + 400}$