A body of emissivity (e = 0.75) has a surface area of 300 cm^2 and a temperature of 227 °C are kept in a room at temperature (27 °C). Using the Stephens Boltzmann law, calculate the value of the net power (in W) emitted by the body. (? = 5.67x10^-8 Wm^-2K^-4)
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Step 1
First, we need to convert the given temperatures from Celsius to Kelvin. To do this, we add 273.15 to each temperature: T1 = 227°C + 273.15 = 500.15 K (temperature of the body) T2 = 27°C + 273.15 = 300.15 K (temperature of the room) Show more…
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