00:01
Given in the question, given that the digits are from 0 to 9, therefore, the digits can be 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9.
00:28
Now the required probability is the required probability is equal to, that is, probability of even number or greater than 4.
00:47
Probability of getting an even number or greater than 4.
01:03
This is represented mathematically as p of a.
01:09
Union b where p of a is the event of getting an even number and p of v is the event of getting a number greater than 4 minus p of a intersection b which means that even number and greater than 4 simultaneously now we have probability of getting an even number is 0 4 4 6 and 8 plus probability of getting a number greater than 4 is p of 5, 6, 7, 8, 9 minus...