00:01
Okay, for your question, you're told that a random sample of 12 jars has been taken from the production line and tested by quality control.
00:09
The sample was found to have a mean of 93 .50 milliliters, and you were told that the standard deviation for the sample is 7 .38 milliliters.
00:26
Now, there's a couple important pieces of information here before i move forward.
00:30
You are told that the amount of liquid dispensed by the machine into the bottles forms a normal distribution.
00:39
That is very crucial that we were told that it was a normal distribution for when we find the critical value.
00:48
Because since we know that the population is a normal distribution, we are allowed to use a z critical value.
00:59
If we would have not known that it was a normal distribution, we would have had to use a t critical value and work with something called degrees of freedom.
01:10
You can avoid degrees of freedom if your sample size is large enough.
01:15
The boundary is usually 30, and ours is well below 30.
01:19
So if i wouldn't have been told normal distribution, i would be looking for a t.
01:25
But since we were told, i'll be looking for a z.
01:27
And we'll get into that here in a minute.
01:29
Then i'll be looking for a z using a z table for the critical value.
01:34
Your question is to find the upper limit of a 90 % confidence interval.
01:40
So let's draw out what that actually means.
01:49
So we have our normal distribution and your x bar, your mean is going to be in the center of that, 93 .50.
01:58
And we want to block off the middle 90 % of data.
02:06
We want to find out what the amount of milliliters would be here, potentially, although your question only wants the high limit.
02:16
We could find either with our confidence interval.
02:19
The key to finding that is to going to be to finding our critical z value for our confidence interval formula.
02:30
And to do that, i know this is 90 % between the two.
02:34
That's what we're setting up.
02:35
We first try to find what are called alpha levels.
02:40
And to do that, i'm doing 100 % minus 90%, which would be 10%.
02:48
And then i split that into two because i have those two tails.
02:52
So what i know is that there's 5 % in each tail.
02:57
There's 5 % in each tail...