b. $((P \rightarrow Q) \land Q \implies \neg P$ \begin{tabular}{|c|c|c|c|c|c|} \hline P & Q & P \rightarrow Q & \neg P & (P \rightarrow Q) \land Q & (P \rightarrow Q) \land Q \implies \neg P \\ \hline T & T & T & F & T & F* \\ \hline T & F & F & F & F & T \\ \hline F & T & T & T & T & T \\ \hline F & F & T & T & F & T \\ \hline \end{tabular}
Added by Kristen C.
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