Br NaNH2 Sn1 Sn2 E1 E2 1) LDA, low temp 2) CH3CH2Br Sn1 Sn2 E1 E2 HBr Sn1 Sn2 E1 E2
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Step 1: When the compound reacts with NaNH3, it undergoes an Sn2 reaction, resulting in the formation of Mhm. Show more…
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