00:01
Hi students, first let's note down the given parameters.
00:07
So density of water is given here, let it be rho w, it is given as 998 kg per meter cube.
00:17
Density of oil is given, let it be rho o, it is given as 912 kg per meter cube.
00:25
And density of mercury hg is also given, let it be rho m, it is given as 13546 kg per meter cube.
00:37
Let the pressure in pipe a be pa, pressures are also, let pressure in pipe a be pa, pressure in pipe b be pb, then we can write pa plus rho w into g into 0 .15 is equal to p3.
01:06
So here recall the equation for liquid pressure, p is equal to rho gh.
01:15
Now we can write p3 plus rho m into g into 0 .15 is equal to p4.
01:28
Now by pascal's law, by pascal's law as 0 .2 and 0 .4, refer the diagram, 0 .2 and 0 .4 lies at the same level.
01:54
As 0 .2 and 0 .4 lies at the same level by pascal's law, we know that the pressure will be the same.
02:01
So we can write p1 is equal to, sorry p2 is equal to p4, p2 is equal to p4.
02:11
So we can write p1 is equal to p2 minus density of oil into g into 0 .3.
02:30
Now by pascal's law, we can write p1 is equal to so pb is equal to pa plus rho wg into 0 .15 plus rho mg into 0 .15 minus rho og into 0 .3...