00:01
Here we have a truck which is suspending a person in a bucket with mass m sub 2 from a beam with mass m and length l.
00:14
We're told that at a certain point, this mass loses its acceleration, loses its support, and begins to free fall about this.
00:33
Axis here and we want the angular acceleration of this bucket so to get the angular acceleration we first need to figure out the force that is generating this angular acceleration now this force will be the gravitational force f sub g the total gravitational force will be the sum of the two mass m plus n sub 2 times g now in the rotational direction we need the force that is perpendicular to the bar that supports the mass so the rotational the force that causes the rotation should be f sum r m plus m sub 2 g cosine of data where we're told what data is now, we need the torque.
01:45
Now, this torque will be the center of mass of this whole or bar and n mass arrangement times f subar.
01:56
Thus, we need to compute the center of mass, which comes from the center of, the average of the center of masses of the bar and the mass at the end.
02:11
The center of mass for the bar is at the point l over 2, and the center of mass of the mass is at point l.
02:21
So the total center of mass should be m times l over 2 plus m sub 2 times l, divided by the total mass, m plus m over 2.
02:33
Therefore, the torque should be m over 2 plus m over 2 plus m sub 2, l g cosine data, where we've plugged in the center of mass here and this force here...