00:01
We want to find the angular acceleration of this entire arrangement of a bar of mass m and length l, with a mass m sub 2 fixed at the end of it, when this whole structure is raised by an angle theta off of the horizontal.
00:21
The force which will cause this system to rotate will be the gravitational force.
00:28
Now, we need the rotational part of this gravitational force, which will be the part that is perpendicular to the axis of rotation.
00:41
Or rather not the axis of rotation, but which is perpendicular to the bar.
00:46
Now, it turns out that this rotational force, f subar, will be the total mass, m plus m sub 2, g times cosine theta.
01:02
Now we want the torque from this rotational force, which should be xcm times f subbar.
01:15
The xcm is the center of mass of the whole arrangement.
01:19
Thus, we need to get the center of mass from the center of mass of the bar, which is l over 2, and the position of the sec of m sub 2, the second mass...