Question

$\bullet$ In an $R-L-C$ series circuit the magnitude of the phase angle is $54.0^{\circ},$ with the source voltage lagging the current. The reactance of the capacitor is $350 \Omega,$ and the resistor resistance is 180$\Omega .$ The average power delivered by the source is 140 $\mathrm{W}$ . Find (a) the reactance of the inductor; (b) the rms current; (c) the rms voltage of the source.

          $\bullet$ In an $R-L-C$ series circuit the magnitude of the phase
angle is $54.0^{\circ},$ with the source voltage lagging the current. The
reactance of the capacitor is $350 \Omega,$ and the resistor resistance is 180$\Omega .$ The average power delivered by the source is 140 $\mathrm{W}$ . Find (a) the reactance of the inductor; (b) the rms current; (c) the rms voltage of the source.

Added by Katherine R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Narayan Hari

12/14/2021

Step 1

0^{\circ}$, $X_C = 350 \Omega$, $R = 180 \Omega$ Using the formula $\tan \theta = \frac{X_C - X_L}{R}$, we can solve for $X_L$: $\tan 54.0^{\circ} = \frac{350 - X_L}{180}$ $X_L = 350 - 180 \tan 54.0^{\circ}$ $X_L = 102.25 \Omega$ Therefore, the reactance of the Show more…

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$\bullet$ In an $R-L-C$ series circuit the magnitude of the phase angle is $54.0^{\circ},$ with the source voltage lagging the current. The reactance of the capacitor is $350 \Omega,$ and the resistor resistance is 180$\Omega .$ The average power delivered by the source is 140 $\mathrm{W}$ . Find (a) the reactance of the inductor; (b) the rms current; (c) the rms voltage of the source.