Question

“Bullying,” according to noted expert Dan Olweus, “poisons the educational environment and affects the learning of every child.” Bullying and victimization are evident as early as preschool, with the problem peaking in middle school. Suppose you are interested in the emotional well-being not only of the victims but also of bystanders, bullies, and those who bully but who are also victims (bully-victims). You decide to measure depression in a group of victims and a group of bystanders using an 18-item, 5-point depression scale. Assume scores on the depression scale are normally distributed. The group of 23 victims scored an average of 40.1 with a sample standard deviation of 10.1 on the depression scale. The group of 28 bystanders scored an average of 46.8 with a sample standard deviation of 11.6 on the same scale. Suppose you intend to conduct a hypothesis test on the difference in population means. In preparation, you call the sample of victims sample 1 and the sample of bystanders sample 2. Organize the provided data by completing the following table: Sample 1 Sample 2 n1 = n2 = ?1 = ?2 = M1 = M2 = ?1 = ?2 = s1 = s2 =

          “Bullying,” according to noted expert Dan Olweus, “poisons the educational environment and affects the learning of every child.” Bullying and victimization are evident as early as preschool, with the problem peaking in middle school. Suppose you are interested in the emotional well-being not only of the victims but also of bystanders, bullies, and those who bully but who are also victims (bully-victims). You decide to measure depression in a group of victims and a group of bystanders using an 18-item, 5-point depression scale. Assume scores on the depression scale are normally distributed. The group of 23 victims scored an average of 40.1 with a sample standard deviation of 10.1 on the depression scale. The group of 28 bystanders scored an average of 46.8 with a sample standard deviation of 11.6 on the same scale. Suppose you intend to conduct a hypothesis test on the difference in population means. In preparation, you call the sample of victims sample 1 and the sample of bystanders sample 2. Organize the provided data by completing the following table: Sample 1 Sample 2 n1 = n2 = ?1 = ?2 = M1 = M2 = ?1 = ?2 = s1 = s2 =

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“Bullying,” according to noted expert Dan Olweus, “poisons the educational environment and affects the learning of every child.” Bullying and victimization are evident as early as preschool, with the problem peaking in middle school. Suppose you are interested in the emotional well-being not only of the victims but also of bystanders, bullies, and those who bully but who are also victims (bully-victims). You decide to measure depression in a group of victims and a group of bystanders using an 18-item, 5-point depression scale. Assume scores on the depression scale are normally distributed. The group of 23 victims scored an average of 40.1 with a sample standard deviation of 10.1 on the depression scale. The group of 28 bystanders scored an average of 46.8 with a sample standard deviation of 11.6 on the same scale. Suppose you intend to conduct a hypothesis test on the difference in population means. In preparation, you call the sample of victims sample 1 and the sample of bystanders sample 2. Organize the provided data by completing the following table: Sample 1 Sample 2 n1 = n2 = ?1 = ?2 = M1 = M2 = ?1 = ?2 = s1 = s2 =

Added by Jim B.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Shaiju T

04/22/2022

Step 1

1)^2 + (28 - 1)(11.6)^2}{23 + 28 - 2}} \] \[ s_p = \sqrt{\frac{(22)(102.01) + (27)(134.56)}{49}} \] \[ s_p = \sqrt{\frac{2244.22 + 3631.12}{49}} \] \[ s_p = \sqrt{\frac{5875.34}{49}} \] \[ s_p = \sqrt{119.897} \] \[ s_p = 10.95 \] Show more…

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Bullying, according to noted expert Dan Olweus, poisons the educational environment and affects the learning of every child. Bullying and victimization are evident as early as preschool, with the problem peaking in middle school. Suppose you are interested in the emotional well-being not only of the victims but also of bystanders, bullies, and those who bully but who are also victims (bully-victims). You decide to measure depression in a group of victims and a group of bystanders using an 18-item, 5-point depression scale. Assume scores on the depression scale are normally distributed. The group of 23 victims scored an average of 40.1 with a sample standard deviation of 10.1 on the depression scale. The group of 28 bystanders scored an average of 46.8 with a sample standard deviation of 11.6 on the same scale. Suppose you intend to conduct a hypothesis test on the difference in population means. In preparation, you call the sample of victims sample 1 and the sample of bystanders sample 2. Organize the provided data by completing the following table:

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00:01 Hey guys in this question we have been given that the sample mean sample mean x x1 bar equals to 40 .1 and the sample is standard sample one is standard deviation s1 equals to 10 .1 and sample one size n1 equals to 23 and for sample 2 mean is mean x2 bar is given 46 .8 and standard deviation s2 is given 1 .11 .6 and sample 2 size n2 is given 28.

00:37 So as population population variants are not equal we can assume there are these are the independent samples not degree of freedom for dependent sample is so the formula for degree of freedom is equal to s1 squared by n1 plus s2 square divided by n2 and this is whole square and this whole divided by s1 squared by n1 whole square divided by n1 minus 1 plus h2 squared divided by n2 whole square divided by n 2 2 minus 1 so after putting all this value so the degree of freedom will be 49 and so step 1 will be the null hypothesis s not is null hypothesis null hypothesis null hypothesis mu 1 minus mu 2 equals to 0 and alternate hypothesis h1 so this is h0 and h1 h a alternative higher processes is mu1 minus me 2 is not equal to 0 mu 1 minus mu 2 is not equals to 0 so this is even equal to mu and minus me 2 equals to 0 so this is two tail test so we can say that we will use sample t statistics so the formula for sample t statistics will be t test t test equals to x1 bar minus x2 bar minus nu 1 minus new 2 divided by under root s1 bar divided by n1 plus s2 bar divided by n2 so this is going to be after putting all these values so this is the t test so let me just write that t test t test is going to be minus 2 .20 this is our test statistics and p value so the p value is, so p value is, we can find out p value.

02:51 So p value is given by p of probability of t is less than minus 2 .20 and this is going to be 0 .0324.

03:04 So using t table or t dish, we can find out.

03:09 So the significance level alpha is, so this is 3 to 4.

03:14 So let me write that.

03:16 So significance level alpha equals rule is always 0 .05...

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