00:01
Okay, so we have a sample here of 19 coupon clippers, and they had a mean age of 33 .4, and a standard deviation of 9 .5.
00:10
And then there was another sample of 35 ecoupon users that had a sample mean of 41 .5, and a standard deviation of 5 .6.
00:22
We are to assume the standard deviations are not the same, so we're not going to pool them.
00:26
And we're going to use alpha equals 0 .02 and find the mean ages of the two groups.
00:36
Okay, so first of all, it wants us to...
00:46
Okay, so we have a sample here.
00:49
So when we've got this unequal variance thing, we have this kind of nasty thing for the degrees of freedom, right? we've got the squared variances added together divided by the same number s1 squared over n1 over n minus 1 plus s2 squared over n2 minus 1 plus s2 squared over n2 minus 1.
01:34
Give me a second to put that into my calculator.
01:37
Okay, so we have a sample.
01:39
Okay, so i put that entire thing into my calculator with all the s's.
01:43
Remember, for this one, it's because it doesn't actually matter which one's one and two as long as you keep them straight.
01:50
But just remember to use lots and lots of parentheses.
01:53
And i end up with degrees of freedom 110.
02:03
Okay, so we have a sample.
02:05
Okay, sorry, just kidding.
02:07
I realized that put something in wrong.
02:09
So the degrees of freedom came down to 29 .75, which makes a lot more sense because your degrees of freedom should never ever be bigger than both of your ends added together.
02:22
So we're going to round that down then to 29.
02:26
So now we're using alpha equals 0 .02, and we're testing the hypothesis of no difference.
02:31
So it says that they want us to assume that each coupon as the first sample.
02:37
So it shouldn't really matter, though, for the test statistic...