By what factor is the apparent weight of the mass when it is submerged in water, less than the true weight when out of the water? The density of the mass is 2400 kg/m3 and the density of water is 997 kg/m3
Added by Katie P.
Step 1
First, we need to find the buoyant force acting on the mass when it is submerged in water. The buoyant force is given by Archimedes' principle, which states that the buoyant force is equal to the weight of the fluid displaced by the object. Show more…
Show all steps
Your feedback will help us improve your experience
Adi S and 63 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
"The density of steel is 9000. kg/m3 and the density of water is 1000. kg/m3. If a cube of steel that is 0.100 m on each side is placed in a tank of water and weighed while under water, what is the apparent weight of the cube?"
Deepak J.
A solid of density 5000 kg/m3 weighs 0.5 kg f in air. It is completely immersed in water of density 1000 kg/m3. (a) Calculate the apparent weight of the solid in water. (b) What will be its apparent weight if water is replaced by a liquid of density 8000 kg/m3.
Jaya M.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD