00:01
Hello, in this question first we have to calculate the escape velocity from the mars surface.
00:05
The escape velocity can be expressed as v is equal to root of gm divided by r.
00:14
Here g is gravitational constant, m is the mass of mars and r is the radius of mars.
00:21
So it equals root of, let's substitute the values.
00:26
J is 6 .67 into 10 raised to minus 11, newton, meter square per kilogram square into m is 6 .39 into 10 square kilogram.
00:41
The whole divided by r is 3 .39 into 10 raised to 6 meter.
00:50
So it equals 1 .6 into 10 raise to minus 7 meter per second.
00:56
Therefore the escape velocity from the mars surface is obtained as v is equal to 1 .6 .6.
01:02
X x x x x to minus 7 m per second.
01:06
Now in part 2 of the question, let's apply conservation of energy to a body projected with escape velocity.
01:15
Applying conservation of energy we can write k -e -i plus p -e -i equals k -e -f plus p -e -f.
01:29
Here k -e -i and p -e -e -i respectively the kinetic and potential and potential...