At what temperature is the rms speed of a molecule of neon gas equal to 2200 m/s? The mass of a neon molecule is 3.340×10^-26 kg. If you wished to reduce the rms speed of the molecules in neon gas to 1100 m/s, what temperature would be required?
Added by Stephen M.
Close
Step 1
We know that the rms speed (v_rms) of a gas molecule is given by the equation: v_rms = √(3kT/m) where k is the Boltzmann constant (1.38 x 10^-23 J/K), T is the temperature in Kelvin, and m is the mass of the molecule. Show more…
Show all steps
Your feedback will help us improve your experience
Madhur L and 88 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
At what temperature would the rms speed of neon-20 atoms equal the following speeds? (Note: The mass of a neon-20 atom is 3.32 x 10^-26 kg.) (a) the escape speed from Earth, 1.12 x 10^4 m/s (b) the escape speed from the Moon, 2.37 x 10^3 m/s
Madhur L.
At what temperature does the rms speed of $\mathrm{O}_{2}$ molecules equal $400 . \mathrm{m} / \mathrm{s} ?$
Find the rms velocity (vrms) of Neon gas at 67 °C. R (Gas constant) = 8.314 kJ / mole k (Boltzmann constant) = 1.38 x 10^-23 J/K 1 cal = 4.186 J 1 atm = 1.031 x 10^5 Pa NA (Avogadro’s number) = 6.0221415 × 10^23 mol^-1 1 atomic unit (u) = 1.66x10^-27 kg Water density: pw = 1000kg/m^3 Vapor density: pv = 0.60 kg/m^3
Adi S.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD