C2h4g h2g xrightarrowtextplatinum c2h6g c2h4g is reduced by...

C$_{2}$H$_{4}$(g) + H$_{2}$(g) $\xrightarrow{\text{platinum}}$ C$_{2}$H$_{6}$(g) C$_{2}$H$_{4}$(g) is reduced by H$_{2}$(g) in the presence of a solid platinum catalyst, as represented by the equation above. Factors that could affect the rate of the reaction include which of the following? I. Changes in the partial pressure of H$_{2}$(g) II. Changes in the particle size of the platinum catalyst III. Changes in the temperature of the reaction system O I and III only O I, II, and III O II and III only O III only O I and II only

Transcript

00:01 Hello friends, here we are given with five equations, five reactions, reversible reactions, and we have to find out here if we decrease the volume or if we reduce the volume, if we reduce volume, then in which case the equilibrium will shift in the forward direction.

00:27 The equilibrium will shift in the forward direction.

00:31 Sits the equilibrium in the forward direction.

00:41 Now let us see in which case the equilibrium sits in the forward direction in case of a gaseous reaction.

00:47 Let us see.

00:48 We know if we reduce the volume, what will happen? if we reduce the volume, pressure will increase.

00:58 Pressure will increase.

01:02 Now if pressure increases, then if pressure is increases, then what will happen, the equilibrium will sit in the less number of moles, in the direction of less number of, less number of moles.

01:24 Now let us see if we have to find out here, the equilibrium must shift in the forward direction and we know here if volume gets reduced, pressure increases, if pressure increases what will happen, the equilibrium will shift in the towards the less number of moles.

01:39 Therefore, we have to find out if we want to shift the equilibrium in the forward direction, in the forward direction there must be less number of moles.

01:48 Now out of these 5 -1, here in the product side 1 mole of gases there in the reactant side no moles of gases, therefore here more in the forward direction, here 2 moles, here 1, therefore here also more.

02:01 So this is not possible, this is not possible, here 2 moles, here no effect of pressure or reductive of volume.

02:10 Now here also 2 moles, here 1 moles, here also no effect.

02:13 But if we see this one, the last one here, 2 moles, but here in the product side we are having 1 mole.

02:20 That means less number of moles on the forward, forward direction or product side.

02:26 Therefore in the case of e, in the case of e, what will happen? if we reduce the volume, the equilibrium shift we will shift in the forward direction.

02:39 Now coming to the second question, we are given with hydrogen plus iodine gives rise to 2 h and delta h is greater than 0...

Question

Please give Ace some feedback