caculate the ph and pOH for each solutions with the following hydrogen ion or hydroxide ion concentration Solution A (H+) -2.29810^-8 M PH and POH Solution B (OH-)=2.57*10^-4 M Ph and pOH
Added by Hagop K.
Step 1
298 x 10^-8 M pH = -log[H+] pH = -log(2.298 x 10^-8) pH = -(-7.64) pH = 7.64 pOH = 14 - pH pOH = 14 - 7.64 pOH = 6.36 Show more…
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