Calcium oxide (lime) reacts with carbon dioxide to form calcium carbonate (chalk). CaO(s) + CO2(g) → CaCO3(s) ∆H = –178.4 kJ How many kilojoules of heat are evolved in the reaction of 0.500 kg CaO(s) (molar mass 56.08 g/mol) with an excess of carbon dioxide?
Added by Vanesa L.
Step 1
0.500 kg = 500 g So, the number of moles of CaO = 500 g / 56.08 g/mol = 8.92 mol The reaction shows that 1 mol of CaO reacts with CO2 to produce 1 mol of CaCO3 and releases -178.4 kJ of heat. Show more…
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