Question

Calculate Delta Sdeg univ for the following reaction. Determine if spontaneous or nonspontaneous. T=298K SiO2(s)+4HF(g)->SiF4(g)+2H2O(l) SiO2(s)+4 HF(g) -> SiF4(g)+2 H2O(l) nonspontaneous.T=298 K

          Calculate Delta Sdeg  univ for the following reaction. Determine if spontaneous or nonspontaneous. T=298K
SiO2(s)+4HF(g)->SiF4(g)+2H2O(l)
SiO2(s)+4 HF(g) -> SiF4(g)+2 H2O(l) nonspontaneous.T=298 K
        
calculate delta sdeg univ for the following reaction determine if spontaneous or nonspontaneous t298k sio2s4hfg sif4g2h2ol sio2s4 hfg sif4g2 h2ol nonspontaneoust298 k 96624

Added by Tonya J.

Close

Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
Calculate Delta Sdeg univ for the following reaction. Determine if spontaneous or nonspontaneous. T=298K SiO2(s)+4HF(g)->SiF4(g)+2H2O(l) SiO2(s)+4 HF(g) -> SiF4(g)+2 H2O(l) nonspontaneous.T=298 K
Close icon
Play audio
Feedback
Powered by NumerAI
Danielle Fairburn David Collins
Ivan Kochetkov verified

David Collins and 65 other subject Chemistry 101 educators are ready to help you.

Ask a new question

*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

*

Key Concepts

-
Key Concept
Premium Feature
Explore the core concept behind this problem.
Play button
Key Concept
Premium Feature
Explore the core concept behind this problem.
Your browser does not support the video tag.

*

Recommended Videos

-
from-the-values-given-for-ho-and-so-calculate-go-for-each-of-the-following-reactions-at-298-k-if-the-reaction-is-not-spontaneous-under-standard-conditions-at-298-k-at-what-temperature-if-any-would-the

From the values given for ΔHo and ΔSo, calculate ΔGo for each of the following reactions at 298 K. If the reaction is not spontaneous under standard conditions at 298 K, at what temperature (if any) would the reaction become spontaneous? a) 2PbS(s) + 3O2(g) 🡪 2PbO(s) + 2SO2(g) ΔHo = -844 kJ; ΔSo = -165 J/K b) 2POCl3(g) 🡪 2PCl3(g) + O2(g) ΔHo = +572 kJ; ΔSo = +179 J/K

David C.

given-the-values-of-delta-h_mathrmran-delta-s_mathrmran-text-and-t-text-determine-delta-s_mathrmuniv

Given the values of $$ \Delta H_{\mathrm{ran}}, \Delta S_{\mathrm{ran}}, \text { and } T, \text { determine } \Delta S_{\mathrm{univ}}$$ and predict whether each reaction is spontaneous. $ a.\quad \Delta H_{\mathrm{rxn}}^{\circ}=-95\mathrm{k} J ; \quad \Delta S_{\mathrm{mn}}^{\circ}=-157\mathrm{J} \quad {K} T=298 \mathrm{K} $ $ b.\quad \Delta H_{\mathrm{rxn}}^{\circ}= - 95 \mathrm{k} J ; \quad \Delta S_{\mathrm{mn}}^{\circ}=-157\mathrm{J} \quad {K} T=855\mathrm{K} $ $ c.\quad \Delta H_{\mathrm{rxn}}^{\circ}= + 95 \mathrm{k} J ; \quad \Delta S_{\mathrm{mn}}^{\circ}=-157\mathrm{J} \quad {K} T=298 \mathrm{K} $ $ c.\quad \Delta H_{\mathrm{rxn}}^{\circ}= - 95 \mathrm{k} J ; \quad \Delta S_{\mathrm{mn}}^{\circ}=+157\mathrm{J} \quad {K} T=398 \mathrm{K} $

Chemistry Structure and Properties

calculate-delta-gcirc-at-355-mathrmk-for-each-of-the-reactions-in-question-17-state-whether-the-reac

Calculate $\Delta G^{\circ}$ at $355 \mathrm{~K}$ for each of the reactions in Question 17. State whether the reactions are spontaneous.

Chemistry Principles and Reactions


*

Recommended Textbooks

-
Chemistry: Structure and Properties

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition
achievement 1,680 solutions
Chemistry The Central Science

Chemistry The Central Science

Theodore L. Brown 14th Edition
achievement 1,307 solutions
Chemistry

Chemistry

Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste 10th Edition
achievement 1,176 solutions

*

Transcript

-
00:01 The first chemical reaction is 2pbs solid reacting with 3o2 as a gas to produce 2pbo solid and 2so2 gas.
00:27 Delta g can be calculated by taking delta h, negative 844 kj, and subtracting off t delta s.
00:39 T is 298 kelvin and delta s is negative 165 joules per kelvin.
00:48 Because this is in kj, we need to convert our delta s into kj.
00:52 Negative 165 is negative 0 .165 kj per kelvin and we get negative 794 .8 kj.
01:10 Because it's negative, it is spontaneous.
01:18 For the second reaction, we have 2pocl3 as a gas decomposing into 2pcl3 as a gas plus o2 as a gas.
01:36 Delta g standard can be calculated by taking delta h standard, that is positive 572 kj, subtracting off 298, our kelvin temperature, times delta s.
01:55 Delta s again needs to be converted into kj per kelvin...
Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Join the community

18,000,000+

Students on Numerade


Trusted by students at 8,000+ universities

Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever