00:01
First we'll calculate the e cell standard for the reaction by looking up the reduction potentials for the two half reactions that comprise the overall reaction.
00:11
Then we take the reduction potential for the cathode, the species that is being reduced, in this case that is the tin, with a reduction potential of negative 0 .14, and we subtract off the reduction potential for what is being oxidized and serving as the anode, and we get positive 2 .23 volts.
00:34
Then e cell under the conditions provided can be calculated using the nernst equation.
00:41
E cell equals e cell standard at 25 degrees celsius, which they didn't tell us, so we'll just assume that.
00:51
Then we subtract off 0 .05916 divided by n, n is the moles of electrons transferred.
00:59
Each tin 2 plus takes on two electrons to become tin solid, so n is 2, and then we multiply by the log base 10 of q.
01:11
Q is the ratio of the concentration of the product as the solute divided by the concentration of the reactant as a solute.
01:22
The solids are excluded, magnesium solid and tin solid, and this gives us an e cell of 2 .23 volts.
01:30
Essentially it stays the same as what we had up here...