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General Chemistry II Assignment 7 Voltaic Cell and Organic Chemistry Show your work! 1. Calculate ?G at 25°C for the following reaction, by first calculating ?H and ?S. Once you've found ?H and ?S, solve for ?G using the Gibbs free energy equations. CH3CO2H(l) + 2 O2(g) -> 2CO2(g) + 2 H2O(l) Substance ?H (enthalpy) ?S (entropy) CH3CO2H -484.5 kJ/mol 159.8 J/mol K O2 0 kJ/mol 205.1 J/mol K CO2 -393.5 kJ/mol 213.7 J/mol K H2O -241.8 kJ/mol 188.8 J/mol K

          General Chemistry II
Assignment 7
Voltaic Cell and Organic Chemistry
Show your work!
1. Calculate ?G at 25°C for the following reaction, by first calculating ?H and ?S. Once you've found ?H and ?S, solve for ?G using the Gibbs free energy equations.
CH3CO2H(l) + 2 O2(g) -> 2CO2(g) + 2 H2O(l)
Substance
?H (enthalpy)
?S (entropy)
CH3CO2H
-484.5 kJ/mol
159.8 J/mol K
O2
0 kJ/mol
205.1 J/mol K
CO2
-393.5 kJ/mol
213.7 J/mol K
H2O
-241.8 kJ/mol
188.8 J/mol K

General Chemistry II
Assignment 7
Voltaic Cell and Organic Chemistry
Show your work!
1. Calculate ?G at 25°C for the following reaction, by first calculating ?H and ?S. Once you've found ?H and ?S, solve for ?G using the Gibbs free energy equations.
CH3CO2H(l) + 2 O2(g) -> 2CO2(g) + 2 H2O(l)
Substance
?H (enthalpy)
?S (entropy)
CH3CO2H
-484.5 kJ/mol
159.8 J/mol K
O2
0 kJ/mol
205.1 J/mol K
CO2
-393.5 kJ/mol
213.7 J/mol K
H2O
-241.8 kJ/mol
188.8 J/mol K

Added by Abrianna G.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert David Collins

05/07/2023

Step 1

5 kJ/mol + 2 * -241.8 kJ/mol) - (-484.5 kJ/mol) ∆H = (-787 kJ/mol - 483.6 kJ/mol) - (-484.5 kJ/mol) ∆H = -1270.6 kJ/mol + 484.5 kJ/mol ∆H = -786.1 kJ/mol Show more…

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Calculate ΔG at 25°C for the following reaction, by first calculating ΔH and ΔS. Once you’ve found ΔH and ΔS, solve for ΔG using the Gibbs free energy equations. CH3CO2H(l) + 2 O2(g) -> 2CO2(g) + 2 H2O(l) Substance ΔH (enthalpy) ΔS (entropy) CH3CO2H -484.5 kJ/mol 159.8 J/mol K O2 0 kJ/mol 205.1 J/mol K CO2 -393.5 kJ/mol 213.7 J/mol K H2O -241.8 kJ/mol 188.8 J/mol K