Calculate ΔG° for a reaction for which ΔH° = 24.6 kJ and ΔS° = 132 J/K at 298 K. Is the reaction spontaneous under these conditions?
Added by Michael M.
Step 1
6 kJ ΔS° = 132 J/K T = 298 K Convert ΔS° to kJ/K: ΔS° = 132 J/K = 0.132 kJ/K ΔG° = 24.6 kJ - (298 K * 0.132 kJ/K) ΔG° = 24.6 kJ - 39.336 kJ ΔG° = -14.736 kJ Show more…
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