00:01
For this question, we're given three chemical reactions with known delta h values, and we're asked to determine the delta h value for ch4 gas with one -half -o -2 gas, going to co gas, plus 2h2 gas.
00:26
So to get this overall reaction, we'll need to multiply the first reaction by 1 fourth so that we get half of an oxygen.
00:35
On the left -hand side.
00:37
When we do that, we multiply delta h by one -fourth.
00:41
We'll need to multiply the second reaction by one -fourth so that our carbon dioxide cancel, one -fourth carbon dioxide cancel.
00:58
And then we're going to need to multiply the last reaction by one -half so that we end up with just one methane on the left -hand side.
01:07
A fourth -and -a -fourth gives us one -half, another one half gives us one...