Calculate ionic strength of the following electrolyte...

Calculate the ionic strength of the following electrolyte solutions: (a) 0.04 mol/kg CaCl2(aq) (b) 0.05 mol/kg NaCl(aq) and 0.03 mol/kg CaCl2(aq) (c) 0.04 moles of Al(NO3)3(aq) and 0.06 moles Ca(NO3)2 and 27.778 moles of water.

Transcript

00:01 The question asked to calculate the ionic strength.

00:10 In order to find the ionic strength, we first write the formula for ionic strength.

00:20 That is, first, the ionic strength is denoted with letter i, which is equal to half of summation i from c -i -z -i -square.

00:35 So, here, i is the number of ions, c is the concentration and z is the charge.

00:55 Now we first take the 0 .04 mole divided by kg of c .a .cl2.

01:06 So here the reaction will proceed like c .cl2, the ionic reaction that is cacl2.

01:12 To form ca2 positive or dissociate into ca2 positive and 2cl negative.

01:21 Now here, i is equals to half of 0 .04 multiply 2 square addition 2 .04 multiply 0 .04 multiply negative 1 square.

01:40 Now here we get 0 .12 mole divided by kg.

01:47 In the second part, we have given 0 .05 mole divided by kg of nacl reacts with 0 .03 mole of cl 2.

02:14 Now here we say that nacl will dissociate to form na positive addition cl negative and when cacl 2 will dissociate it will form ca2 positive addition to cl negative so from here i is equal to 1 divided by 2 0 .05 multiply 1 square addition 0 .05 multiply negative 1 square addition 0 .3 multiplied 2 square addition 2 multiply 0 .03 multiply 0 .03 multiply 0 .03 multiply minus square.

02:57 Now here we get 1 divided by 2 0 .10 addition 0 .03 multiply 4 addition 0 .06.

03:08 So from here we get 0 .14 more divided by k .0 .0 .0 .4 more divided by kg.

03:14 For third one, 0 .04 moles of alno3 holds thrice and 0 .06 moles of ca no3 whole thrice is used over here.

03:43 So we first calculate the water moles that is equal to 20...

Question

Calculate the ionic strength of the following electrolyte solutions: (a) 0.04 mol/kg CaCl2(aq) (b) 0.05 mol/kg NaCl(aq) and 0.03 mol/kg CaCl2(aq) (c) 0.04 moles of Al(NO3)3(aq) and 0.06 moles Ca(NO3)2 and 27.778 moles of water.

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