00:01
So for this question, we're asked to calculate the activation energy given these values.
00:08
So the equation that we're going to use is that the natural log of k1 divided by k2 is equal to the activation energy divided by r, the gas constant, times t1 minus t2, divided by t2, divided by t1.
00:36
X2.
00:37
So we have all of these values given to us, so we just have to solve for the energy.
00:44
So let's start plugging in our values.
00:47
So we have the natural log of k1, which is 3 .3, divided by k2, which is 12 .1.
00:56
It is equal to the activation energy, which is what we're trying to find, divided by r the constant, which is 8 .314, joules.
01:06
Per moles times kelvin times t1, 650 minus temperature 2, which is 800.
01:21
I'm sorry, this is in kelvin, divided by t1 650 times t2, which is 800.
01:31
Now we just got to plug in our calculator.
01:35
I like to do each side separately and then solve for ea.
01:40
So 3 .3 divided by 12 .1...