00:01
So to solve for this, we'll need the molar heat of fission for methanol.
00:08
So it is not given in the problem, but this could be easily looked up in standard reference materials.
00:16
So i have already looked for it, and these are the values that i found.
00:21
We have 3 .215 kilojoules per mole.
00:27
This is the molar heat of fusion from methanol and then the melting point of methanol.
00:32
The melting point is equivalent to negative 97 .53 degrees celsius.
00:41
That's the mounting point of methanol.
00:43
And then for the specific heat of methanol, also write this as 2 .53 joules per grams.
00:58
Kelvin.
00:59
Okay, so we will be using this values right here.
01:02
It is not given in the problem again, but we could look this up in standard reference materials.
01:08
So how do we find the heat? q therefore heat is there for equivalent to the mass of, it's not mass rather, since we have the molar heat of fusion, so that means n, number of moles, n multiplied by the heat of fusion, and then we add the multiplied mass multiplied by the specific heat and then change in temperature.
01:46
Okay, so molar heat of fission will be used for the face change of methanol, okay? so since our temperature is beyond the melting temperature of methanol, okay? okay, so looking for q, we have, how do we get n number of moles? we know that we have 53 .2 grams of methanol, and then to convert this to number of moles, we'll just have two divided by the molar mass, 32 .04 grams for every mole of methanol or ch30h.
02:26
Okay, and then the ki -itap fusion is we have 3 .5...