Calculate the binding energy per nucleon for a nucleus of calcium-40 ( _(20)^(40)Ca ), given the following information:
Mass of Nucleus =39.9675912amu
Mass of Proton =1.007276amu
Mass of Neutron =1.008685amu
1.00amu =1.66 imes 10^(-27) kilograms .
Speed of Light =C=3.00 imes 10^(8) meters / second .
1.49 imes 10^(-10) Joules
1.31 imes 10^(-12) Joules
5.25 imes 10^(-11) Joules
2.62 imes 10^(-12) Joules
Calculate the binding energy per nucleon for a nucleus of
calcium-40 (402oCa ), given the following information:
Mass of Nucleus=39.9675912amu
Mass of Proton =1.007276amu
Mass of Neutron =1.008685 amu
1.00 amu = 1.66 x 10-27 kilograms.
Speed of Light = C = 3.00 x 10 meters / second.
O 1.49 x 10-10 Joules
O 1.31 x 10-12 Joules
O 5.25 x 10-11 Joules
O 2.62 x 10-12 Joules