Calculate the buoyant force on a rock with a mass of 82 kg and a density of 2,800 kg/m3 when fully submerged in water with a density of 1,000 kg/m3.
Added by Jason T.
Step 1
Given: Mass of the rock, m = 82 kg Density of the rock, Ļ = 2800 kg/m^3 Volume of the rock submerged = Mass of the rock / Density of the rock Volume = 82 kg / 2800 kg/m^3 Volume = 0.0293 m^3 Show moreā¦
Show all steps
Your feedback will help us improve your experience
Mahendra Kumar and 73 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A rock with a volume of 0.2 m3 is fully submerged in alcohol having a density of 0.8 g/cm3. What is the buoyant force in newton acting on the rock?
Adi S.
A rock of mass 18.8 kg and volume 0.004 m3 sits on the bottom of a saltwater aquarium filled with water of density 1.043 x 103 kg/m3. The buoyant force acting on it is ______ N.
(I) A geologist finds that a Moon rock whose mass is 9.28 $\mathrm{kg}$ has an apparent mass of 6.18 $\mathrm{kg}$ when submerged in water. What is the density of the rock?
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD