00:01
Here, in this question, first we can write down the given values, that is, the value of mass is equal to 93 .3 grams, the value of change in temperature that is our delta t means t2 minus t1 is equal to 48 degree celsius and the value of c constant, this is our specific heat, the value of this is equal to 4 .184 joule per gram.
00:41
So, first we can find out the heat absorbed in water, that is equal to q is equal to m multiplied by c into delta t.
00:59
So, q is equal to 93 .3 grams multiplied by 4 .184 joule per gram multiplied by the value that is 48 degree celsius.
01:14
So, q is equal to 18705 .6 joule.
01:21
Now, we can find out the value of heat absorbed by solid, that is equal to q is equal to m multiplied by delta h reaction...