Calculate the change in the standard Gibbs energy when 1 mol of ice melts at 0 °C and 1.013 × 105 Pa. ΔfusHѲ = + 6.01 kJ mol–1 ΔfusSѲ = + 22 J mol–1 K–1
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Step 1
In this case, we are given ΔfusHѲ (the standard enthalpy change of fusion) as +6.01 kJ mol–1, ΔfusSѲ (the standard entropy change of fusion) as +22 J mol–1 K–1, and the temperature as 0 °C. First, we need to convert the temperature to Kelvin. We do this by Show more…
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