00:01
Students, we have given the three particle system.
00:05
One particle of mass 2 .4 kg, having the coordinates x1, y1 and z1 equals 2 .2, 4 .5 and 3 .1.
00:21
Similarly, mass of the second particle is 6 .1 kgs and the coordinates are x2y2 .2 .2 .2.
00:32
And z2 which is 3 .4, 0 .6 and 2 .6.
00:40
Now comes the mass of the third particle which is 3 .8 kgs and the coordinates are x3, y3 and z 3 which is 9 .1 minus 9 .4 and minus 5 .8.
01:01
This is given to us and we have to find the coordinates of center of mass.
01:07
Let that be x bar, y bar and z bar.
01:13
Now, to find it x coordinate of the center of mass, that will be m1x1 plus m2x2 plus m3x3, whole divided by the sum of masses.
01:32
Of the particle.
01:36
So writing it now x bar is equal to m1 is 2 .4 times 2 .2 plus 6 .1 times 3 .4 plus 3 .8 times 9 .1 whole divided by 2 .4 plus 6 .1 plus 3 .8 and after solving this we get the x -coordinary of the center of mass 4 .92 centimeters.
02:11
Similarly, for the y coordinate of the center of mass, the formula will be m1y1 plus m2y2 plus m3 y3, whole divided by the sum of masses, m1, m2 plus m3.
02:30
Again putting the values i get, m1 is 2 .4, 4 .5 plus 6 .1 times 0 .6 plus 3 .8 times minus 9 .4...