Calculate the coordinates of the unit vector d perpendicular to the following vectors \begin{bmatrix} 3 \\ 0 \\ 3 \\ 0 \end{bmatrix}, \begin{bmatrix} 9 \\ 0 \\ -9 \\ 3 \end{bmatrix}, \begin{bmatrix} 0 \\ 54 \\ 0 \\ 4 \end{bmatrix} Write the result approximated to the third decimal place and with the first coordinate always positive (e.g. multiply the vector by -1 if its first coordinate is negative)
Added by Elizabeth R.
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a x b = (0*0 - 0*3) i - (0*0 - 0*3) j + (6*0 - 3*0) k = 0i - 0j + 0k = 0 Since the cross product is zero, vectors a and b are parallel, and any vector perpendicular to them will be perpendicular to vector c as well. Show more…
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