00:01
For the given circuit we have to find out the current through each resistor.
00:06
Consider the current drawn from the 12 volt battery is i at the junction where the two battery meets with 4 ohm.
00:25
The current coming from 12 volt is i1 from 5 volt is i2 and the current going in the 4 ohm resistor is i3.
00:37
Again the current entering in the 12 volt battery is i1 and in the 5 volt battery is i2.
00:49
At this junction we can write i1 plus i2 equals i3.
00:56
Now let's move along this loop, loop 1.
01:00
Then for loop 1 we can write from ohm's law 12 minus i3 times 4 minus i1 times 3 equals 0.
01:16
And if we substitute i3 as i1 plus i2 then we can write 12 minus i1 plus i2 times 4 minus 3 i1 equals 0.
01:28
Then from this we obtain 7 i1 plus 4 i2 equals 12 volt.
01:40
Say this as equation 1.
01:42
Now move in the second loop.
01:45
For the second loop we can write 5 minus i1 plus i2 times 4, this is for i3 minus i2 times 2 equals 0...