00:01
Hi everyone, so the question is saying that the resistance of the calvanometer coil is 25 om and the current required for this this is equal to 500m a p .m p .m.
00:14
So this is equal to 500 into delethe minus 3 mp so in the a part of the question the question is saying that so in the diagram how to convert the calvonometer into an ammeter.
00:27
Okay so we have to convert this galvanometer into an ameter and by concluding the short resistance.
00:35
So first of all to convert a galvanometer to convert galvanometer in amygote.
00:48
What we do to convert in a meter? so we connect a sun resistance resistance that means rhth.
01:10
In ferry.
01:11
Okay.
01:13
So we have to convert this in a voltmeter so we have to connect this in series.
01:19
So how will we connect to this? near vh align.
01:23
In this we have our resistance.
01:26
Okay, this is rc.
01:28
Registence that is given and the current that is going here that is equal to ir s.
01:34
Okay, so this is the current iu is going here.
01:38
So this will be divided into two part.
01:41
The lower is the center resistance.
01:44
Okay, so the current that will pass from here will be equal to i minus ir.
01:51
Okay, so this will be the value of current here.
01:54
So this is the main point.
01:56
This is three point here.
01:57
So we can say that it will connect to both of these in pattern, then the current will be divided into two parts.
02:04
This will be one part, this will be another part.
02:06
If total current is i in this path current is going that is equal to irs, so this will be r minus i.
02:13
This current will be i.
02:16
So by certain page, for that, if it connects to resistance in error, then the formula of so maximum current rate by amity there is here.
02:38
This is equal to 20 into 10 x to the power minus 3 mp that is given here...