Question

Calculate the de broglie wavelength of an electron ejected from potassium in a photoelectric effect by a photon of 4000 Angstrom wavelength, given that potassium's work function is 2.2 eV. (1 eV = 1.602 x 10^-19 J)

Name: calculate the de broglie wavelength of an electron ejected from potassium in a photoelectric effect by a photon of 4000 angstrom wavelength given that potassiums work function is 22 ev 1 ev 31045
Uploaded: 2022-08-26T03:58:30-08:00
Duration: 57 s
Channel: Khoobchandra Agrawal
Description: calculate the de broglie wavelength of an electron ejected from potassium in a photoelectric effect by a photon of 4000 angstrom wavelength given that potassiums work function is 22 ev 1 ev 31045

          Calculate the de broglie wavelength of an electron ejected from potassium in a photoelectric effect by a photon of 4000 Angstrom wavelength, given that potassium's work function is 2.2 eV. (1 eV = 1.602 x 10^-19 J)

Added by Vicente C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Khoobchandra Agrawal

08/26/2022

Step 1

To find the energy of the photon, we use the Planck's equation: \( E = \frac{hc}{\lambda} \), where \( E \) is the energy, \( h \) is Planck's constant (6.626 x 10^-34 Js), \( c \) is the speed of light (3 x 10^8 m/s), and \( \lambda \) is the wavelength of the Show more…

Show all steps

Thanks for your feedback!

Calculate the de broglie wavelength of an electron ejected from potassium in a photoelectric effect by a photon of 4000 Angstrom wavelength, given that potassium's work function is 2.2 eV. (1 eV = 1.602 x 10^-19 J)