00:01
In this problem, we're given different formulas, and we're asked about degrees of unsaturation, and we're asked to draw any structures we can for them.
00:09
So first, we have c4, h8.
00:13
So for degrees of unsaturation, this will give us the total number of rings and pie bonds.
00:23
So we multiply the number of carbons by 2 and add 2, subtract the number of hydrogens divide by 2.
00:31
So here we have one degree of saturation.
00:35
So we either have one ring or one pi bond.
00:39
So this is one possible structure.
00:44
We could get something like that.
00:47
And then if we think about this as a ring, we can have a four -membered ring, or we can have a three -membered ring like this.
00:57
So those are your options for that formula.
01:01
Then we have c4h6 so if we look at our molecular formula here for degrees of saturation again we multiply the number of carbons by two add two subtract the number of hydrogens and divide by two so now we get two degrees of unsaturation so we can have two pie bonds we can have a ring and a pie bond or in theory two rings although here that's not feasible...