00:01
In this question, we are assigned to the task to calculate the standard reduction potential, that is e -note, cr2 positive aquas and cr solid for the half -cell reaction, that is cr2 positive aquas, plus 2 electrons gave out cr solid and cr3 positive aquas plus 3 electrons gives out cr solid.
00:40
For this, the electrode potential is given as minus 0 .74 volt and for the reaction cr3 positive aquas plus electrons gives out cr2 positive aquas and e0 for this is given an 0 .41 watt.
01:05
Now we know that delta g is equals to minus n f e not.
01:16
Therefore delta g for this first reaction is minus 3 and is the number.
01:26
Of electrons in volt minus 0 .74 volt into f f is the ferrardous constant similarly delta g for the second reaction is minus 1 into minus 0 .41 volt into f f is the ferrades constant now reverse the second equation and add it to first equation.
02:06
On reversing the equation, we will get 3 positive aquas plus 3 electrons gave out crs and cr2 positive aquas gives out cr3 positive plus electrons.
02:28
Add these two equations...