Question

y t y Z + Z + h Z (a) b (b) y Z y (d) Problem Statement: A simply supported beam is subjected to a uniformly distributed load w over its entire length $L = 1.5 \text{ m}$. The cross section is a square tube as shown in figure (b), with dimensions $b = 6 \text{ cm}$, $h = 9 \text{ cm}$, $t = 0.5 \text{ cm}$. The material has yield strength $S_y = 85 \text{ MPa}$. Calculate: • The distributed load w when the beam yields. Hint: Ignore the rounded corners. You may use Table A-9(7). Answer tolerance = 2%. Be sure to include units and sign (if needed). Notation: $|x| = abs(x)$. All quantities are labeled as positive in the direction shown in the figures. Moment and shear diagrams follow the sign convention described in the textbook. Your answers: w =

          y
t
y
Z
+
Z
+
h
Z
(a)
b
(b)
y
Z
y
(d)
Problem Statement:
A simply supported beam is subjected to a uniformly distributed load w over its entire length $L = 1.5 \text{ m}$. The cross section is a square tube as shown in figure
(b), with dimensions $b = 6 \text{ cm}$, $h = 9 \text{ cm}$, $t = 0.5 \text{ cm}$. The material has yield strength $S_y = 85 \text{ MPa}$.
Calculate:
• The distributed load w when the beam yields.
Hint: Ignore the rounded corners. You may use Table A-9(7). Answer tolerance = 2%. Be sure to include units and sign (if needed). Notation: $|x| = abs(x)$.
All quantities are labeled as positive in the direction shown in the figures. Moment and shear diagrams follow the sign convention described in the textbook.
Your answers:
w =

y
t
y
Z
+
Z
+
h
Z
(a)
b
(b)
y
Z
y
(d)
Problem Statement:
A simply supported beam is subjected to a uniformly distributed load w over its entire length L = 1.5 m. The cross section is a square tube as shown in figure
(b), with dimensions b = 6 cm, h = 9 cm, t = 0.5 cm. The material has yield strength Sy = 85 MPa.
Calculate:
• The distributed load w when the beam yields.
Hint: Ignore the rounded corners. You may use Table A-9(7). Answer tolerance = 2%. Be sure to include units and sign (if needed). Notation: $|x| = abs(x)$.
All quantities are labeled as positive in the direction shown in the figures. Moment and shear diagrams follow the sign convention described in the textbook.
Your answers:
w =

Added by Carol H.

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