The diameter \( d \) is given as 2.053 mm, so the radius \( r \) is half of that.
\[ r = \frac{d}{2} = \frac{2.053 \, \text{mm}}{2} = 1.0265 \, \text{mm} = 1.0265 \times 10^{-3} \, \text{m} \]
The cross-sectional area \( A \) of the wire is given by the formula
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