00:01
Hi, in this question we are given with this cell notation and we are asked to calculate the e -cell value.
00:06
We are given with standard reduction potential values for sn4 plus and ep3 plus in this manner.
00:13
We can say that the one which has higher positive value of standard deduction potential will undergo reduction and the lower one will undergo oxidation.
00:30
We can write the half -cell reactions at cathode, and at anode in this manner.
00:36
We know that at anode, oxidation occurs and at cathode reduction occurs.
00:41
Now we need to balance the number of electrons in both half reactions.
00:45
Therefore, we will multiply the reaction at cathode by two.
00:50
On doing so, we are getting the overall reaction.
00:54
Here we will cancel out these two electrons and we can rewrite it in this manner.
01:00
Now, we will calculate the e0 cell value that will be equal to e .0 oxidation plus e0 reduction...